1. Square:-figure
(1)Area = a2Sq units.
(or)
(2)Perimeter = P =4a
(or)
(3)Digonal (or)length of the rod that can be placed=
2.Rectangle:-figure
(1)Area =
(2)Perimeter = P =
(3)Digonal =
Þb = Öd2-l2 Þl = Öd2-b2
3.If area of plot is given as 'z'm2 and the ratio of l:b is given as x:y, then length is
l = x * [Öz/(x*y)]
b = y * [Öz/(x*y)]
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4.
length required=(length * breadth of a room)/width of the carpet |
5.
No:of stones =(length * breadth of a room)/(length * breadth of a stone) |
6.
A2/A1= (a2/a1)2 = (d2/d1)2 |
7.
8.Circle:-figure
(1)Area =
(2)
(3)Perimeter (or) Circumference =
Where P = 22/7 (or) 3.14 (4)
A = c2/(4 P) (or) c = Ö4 PA = 2ÖPA |
9. % dec in Area =
fs [(r12 - r22)/r12] * 100 |
10. Distance travelled in 'N' revolutions is,
D = N * Pd (or) N = D/(Pd) |
11.Area left ungrazed =
12.Road out of the garden:-figure
(1)Area of the road =
2w[l+b+2w] = [(l+2w)(b+2w)]-(l*b) |
Road inside the garden:-figure
(2)Area of the road =
Two parallel roads:-figure
(3)Area of the road =
13.Traingles:-
(1)Right angled traingles:-figure
Area = (1/2)*b*h
(2)Equilateral traingles:-figure
Area=
Perimeter = P =
Height=
(3)Scalene traingle:-figure
Perimeter = P =
Þs=(a+b+c)/2
Area =
(4)Isosceles traingle:-figure
Perimeter = P
Area =
14.Volumes:- (a)Cube:-figure
(1)Lateral surface area =
(2)Total surface area =
(3)Volume of a solid = Base area * Height =
(4)Diagonal (or) Longest pole = d =
(b)Cuboid:-figure
(1)Lateral surface area = AL =
(2)Total surface area = AT
(3)Volume = V =
(4)Diagonal = d =
(5)No:of boxes =
(lbh)/l1b1h1 = (Volume of big box)/(Volume of small box) |
15.
16.
17.No:of boxes(if areas are given) =
(18)Cylinder:-figure
(1)Lateral surface area = AL =
(2)Total surface area = AT
(3)
(4)Volume = v =
(5)Area of each flat surface i.e of ends =
(19)Cone:-figure
(1)Slant height = L =
(2)Volume of the cone =
(3)Curved surface area of cone =
(4)Total surface area =
(5)
20.
21.Area of circle inscribed in an equilateral traingle is r2.It's height is,
(22)Sector:-figure
(1)
(2)A =
(3)Circumference,c =
(23)Four circular carboard pieces,each of radius 'r'cm are placed in such a way that each piece touches two other pieces.The area of the space enclosed by four pieces is,
(24)Rhombus:-figure
(1)
(2)Area =
(3)Perimeter = P =
(25)Parallelogram:-figure
(1)Area of DleABC
(2)Area of DleACD
(3)Area of parallelogram =
(26)Trapezium:-figure
(1)Area of Trapezium=Area of (DleABC + DleACD)
1/2(ah) + 1/2(bh) = [(1/2)h][a + b] |
(27)Sphere:-figure
(1)Surface area =
(2)Volume =
(3)
(4)
(5)
(6)
28.Area of four walls =
2 * (length + breadth) * height |
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