Friday, October 26, 2007

SIMPLE INTEREST

SIMPLE INTEREST


1.


S.I = PTR/100


P -----> Principal

T -----> Time (in yrs)

R -----> Rate % per anum


2.
Amount = P+S.I


3.TO find the rate of interest per annum when a sum double/triple etc itself in x    years.Then,
[R * T = 100 * (n-1)]


4.
[(R1*T1)/R2*T2) = (N1-1)/(N2-1)]


5.
[(A/S.I = (100/R*T)+1]


6.
[R(or)T = Ö(100*S.I)/P]


7.
[(R1-R2) = (More interest * 100/(P*t))]


8.
A=[(P+S.I) = P(1+(T.R/100))]


9.
[P=(A1*T2-A2*T1)/T2-T1]

		A  --->  Amount

T ---> Time

10.
R=[(A2-A1)/(A1*T2-A2*T1)] * 100


11.
[I = ATR/(100+TR)]


12.If    I1= I2,
[(P1/P2) = (T2.R2)/T1.R1]


13.
[P = (100/Id)/(Rd.T)]


14.
[T = (100.Id/Pd.R)]


15.
[T = (100.Id/P R.d)]


16.
[R = (100.Is/Td.P)]


17.
[Gain = P.Rd.T/100]


18.
[R = (100.ITotal)/(P1.T1+P2.T2+P3.T3)........]


19.
[P=(100.ITotal/(R1.T1+R2.T2+R3.T3+......)]

20.
a[ [100/100] + [(100+R)/100] + (100+2R)/100] + .......] = 0

		a  --->  Annual instalment.
D ---> Amount due

21.
A = P * [ (100+R1+R2+R3)/100]


1 comment:

yuvan said...

Hi! Thanks for information...

Here is the aptitude simple interest questions and answers with explanation.

http://infibee.com/general-aptitude/simple-interest